20y^2+53y+35=

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Solution for 20y^2+53y+35= equation:


Simplifying
20y2 + 53y + 35 = 0

Reorder the terms:
35 + 53y + 20y2 = 0

Solving
35 + 53y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(7 + 5y)(5 + 4y) = 0

Subproblem 1

Set the factor '(7 + 5y)' equal to zero and attempt to solve: Simplifying 7 + 5y = 0 Solving 7 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 5y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 5y = 0 + -7 5y = 0 + -7 Combine like terms: 0 + -7 = -7 5y = -7 Divide each side by '5'. y = -1.4 Simplifying y = -1.4

Subproblem 2

Set the factor '(5 + 4y)' equal to zero and attempt to solve: Simplifying 5 + 4y = 0 Solving 5 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 4y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 4y = 0 + -5 4y = 0 + -5 Combine like terms: 0 + -5 = -5 4y = -5 Divide each side by '4'. y = -1.25 Simplifying y = -1.25

Solution

y = {-1.4, -1.25}

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